The Low Power Desulfator

Help and information for builders

Finished Board


Begin by making sure the 555 is putting out the proper drive waveform to the MOSFET. This is best done with a scope. Using trim pots in place of R1 and R2 will allow for a wide range of conditions and battery types to be accommodated. If you are unfamiliar with 555 operation take a look at this tutorial: http://courses.ncsu.edu:8020/ece480/common/htdocs/480_555.htm. The illustration below shows what the drive signal to the P channel FET should look like (note: invert this waveform for the N channel version) :

555 output

The frequency of the pulse is close to 1000 Hz. The width of the narrow, negative going part controls how long the MOSFET is turned on. The longer it is turned on, the higher is the peak amperage delivered to the battery, up to a point. At present, it isn't known whether it is better to pulse frequently with a small amperage pulse, or whether a slower, higher peak pulse is better. The latter looks to be the best bet however.

NOTE:If you are having trouble with things getting too hot, it is likely that the 50usec pulse width is too long, resulting in L1 saturating. Also, C4 should not get warm, but will if it is a marginal unit with too much ESR (effective series resistance).



waveform

Here is the current pulse created by the circuit. This was taken using a .1 ohm resistor in series with the negative lead. The circuit is showing, given the scope setting, a peak current of over 5 amps. There is quite a bit of high frequency ringing on the leading edge of the pulse. This peak current can be reduced or increased by changing the width of the 555 drive pulse to the MOSFET. For small batteries, it might be wise to reduce the pulse width. For larger units, using heavier duty inductors, a longer pulse would give more current. As the 555 goes low for ~50usec, the MOSFET is turned on. Current flows into L1 from the stored charge in C4. The magnetic field around L1 builds up until Q1 turns off. The field now collapses, and as a result the inductive kick back forces a large current spike which goes from the -12 volt terminal, through D1, through L1, through C4, and into the +12 volt terminal. This is all over in less than 100 usec. The rest of the cycle allows C4 to slowly recharge, at a current of around 50 mA, through L2 until the next firing of Q1. Check the DC current drain of the circuit. It should be less than 100mA, preferably less than 50mA. If you increase the peak current output, the efficiency will go down, and so the DC current drain will go up.

The tireless Don Denhardt has supplied the following data which shows, for the Delevan chokes sold through Digikey, the relation of pulse width to peak current pulse. It shows the diminishing returns due to saturation of the inductors:

Tables showing peak amps
at various pulse widths.
(Pulses in microseconds.)

6 Volt battery

IRF=IRFZ44N
IRL=IRLZ44
L1=(See table)
L2=1000uH

Pulse	IRF	IRL 	IRF	IRL
 Width	220uH	220uH	120uH	120uH

10	.75	.75	0.8	0.8
20	1.2	1.0	1.2	1.2
30	1.6	1.3	1.8	1.6
40	2.0	1.8	2.0	1.8
50	2.2	1.8	2.2	2.0
60	2.4	2.0	2.6	2.2
70	2.8	2.1	2.8	2.5
80	2.9	2.2	3.0	2.8
90	3.0	2.5	3.6	3.1
100	3.2	2.8	4.0	3.8
110	3.6	2.9	4.0	4.0
120	4.0	3.3	4.0	3.9
130	4.6	3.8	---	3.8
140	5.0	4.2	---	---
150	5.1	4.5	---	---
160	5.0	4.6	---	---
170	5.0	4.5	---	---
180	4.9	4.1	---	---


 12 Volt battery

IRF=IRFZ44N
IRL=IRLZ44

Pulse	IRF	IRL 	IRF	IRL	IRF
 Width	220uH	220uH	120uH	120uH	330uH

10	1.2	1.0	1.5	1.2	0.8
20	1.9	1.6	2.2	1.8	1.2
30	2.4	2.0	3.0	2.4	1.6
40	3.0	2.5	3.5	3.5	2.0
50	3.5	3.0	3.5	4.0	2.2
60	4.0	4.2	3.2	4.0	2.5
70	4.0	4.8	---	---	3.2
80	4.0	4.8	---	---	3.5
90	4.0	5.0	---	---	3.5
100	4.0	5.0	---	---	---

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