Reading assignments |
Homework assignments |
|
Chapter 7, section 5 |
Part I, exercises #2,3,6,8,12,14 |
|
Chapter 7, section 6 |
Part I, exercises #2,5,8,11,17 |
|
Chapter 7, section 7 |
Part I, exercises #2,3,5,9 |
Imagine the following argument:
If the Democrats are elected, then we will have higher taxes, more students will go to college, and Medicare costs will continue to rise. If more students go to college, then incomes will rise. If we have higher taxes, then there will be less money for new businesses. Therefore, if the Democrats are elected, then incomes will rise, there will be less money for new businesses, and Medicare costs will continue to rise.
Notice that if someone were to respond that incomes will not rise
because the Republicans will win, the response would be that the argument said that
the effects would result if the Democrats win. In other words, let us assume,
for the sake of the argument, that the Democrats win. Then certain things will happen:
incomes will rise, there will be less money for new businesses, and Medicare costs
will continue to rise. But these three things are conditional on the Democrats winning.
We capture this reasoning in the following way:
1. D [ (T
C)
M] (premise)
2. C
I (premise)
3. T
L (premise)
4. Assume D (for the sake of the argument)
5. Assuming D, we have (T
C)
M (from 1 and 4 by MP)
6. Thus (assuming D) we have C from 5 (by Simp after some moving around)
7. Thus (assuming D) we have I (from 2 and 6 by MP)
8. (Assuming D) we also have L (from 3 and the C we get from 5)
9.(Assuming D) we also have M (from 5)
10. Thus (assuming D) we have (I
L)
M (from 6, 7, and 8)
11. Therefore D [ (I
L)
M]
You'll notice that 10 and 11 are actually saying the same thing.
The way we capture this in a proof is as follows: (1) We will assume the antecedent
of the conclusion, D, as a premise (an assumption for the purposes of conditional
proof, ACP). (2) Then we will prove the consequent of the conclusion, while acknowledging
that these lines are based on that assumption. (3) Finally we will reach our conclusion
by the rule Conditional Proof, CP. The way we indicate that our statements are based
on an assumption is to draw a vertical line to the left of the statement. (The line
would normally be continuous.) Our proof looks like the following:
| 1. D |
|
| 2. C |
|
| 3. T |
/ D |
| | 4. D | ACP |
| | 5. (T |
1,4, MP |
| | 6. T |
5, Simp |
| | 7. T | 6, Simp |
| | 8. C |
6, Comm |
| | 9. C | 8, Simp |
| | 10. M |
5, Comm |
| | 11. M | 10, Simp |
| | 12. I | 2, 9 MP |
| | 13. L | 3, 7 MP |
| | 14. I |
12, 13 Conj |
| | 15. (I |
14, 11 Conj |
| 16. D |
4--15, CP |
The ways to read these lines are as follows:
Line 4: We are assuming D.
Lines 5 through 15: on the assumption of D (and the original premises) we can derive
these statements.
Line 16. Since we have derived line 15, (I
L)
M, on the assumption that D is true, it follows
that D
[ (I
L)
M] must be true. The justification reads: On the assumption of 4 we have derived
15. The 4--15 indicates that a derivation took place between 4 and 15.
Anytime you use an assumption (ACP), you must "discharge" that assumption
by CP. Otherwise the conclusion that you reach is on the basis of an assumption,
not just the original premises.
Conditional proof can also be used more than once, either in sequence,
or with one embedded in another. For an example of the latter case look at our rule
Exportation: [(p
q)
r] :: [p
( q
r)]. Look at the following proof which normally would use this rule, but in which
we will use CP instead:
| 1. (P |
/ P |
| | 2. P | ACP |
| | | 3. Q | ACP |
| | | 4. P |
2,3 Conj |
| | | 5. R | 1,4 MP |
| | 6. Q |
3--5 CP |
| 7. P |
2--5 CP |
My strategy was as follows: I need to get the conclusion P ( Q
R) . So I
should assume its antecendent, P, and try to prove its consequent, Q
R, and then use CP. So now my goal
is to prove Q
R. I do this (again) by assuming its antecendent (Q) and proving its consequent (R),
and then using CP.
One further note about CP. The assumption lines must be inside each other. In other
words, you must discharge the last assumption first.
The Indirect Proof Rule (IP) is based on the fact that if you can
derive a self-contradictory statement from a set of statements, then that set of
statements must be inconsistent. If you assume that all the statements in an inconsistent
set, except one, are true, then the other one must be false. In other words, if we
assume a statement as an assumption, and we can derive a self-contradiction from
it (and the other premises) then the assumption must be false (since we are assuming
our original premises are true). So our method is this: we will assume the negation
of what we are trying to prove. (Say we are trying to prove
p; we will assume p). If, on the
basis of that assumption we can derive a statement of the form q
q, then we can say that
p is true.
This method of reasoning is also called "reductio ad absurdum", the "reducing"
to an absurdity. If anything leads to an absurdity (and a self-contradiction is the
ultimate absurdity), then it must be false.
Look at the following proof using Indirect Proof (IP):
| 1. |
|
| 2. |
/ R |
| | 3. |
AIP |
| | 4. F |
1,3 MP |
| | 5. W | 4, Comm, Simp |
| | 6. |
2,3 MP |
| | 7. W |
5, 6 Conj |
| 8. |
3--7 IP |
| 8. R | 7, DN |
Some comments about this proof: Since I wanted to prove R, I assumed
its opposite as an assumption (AIP). On the basis of this assumption (note the assumption
line) I derived a self-contradiction: W
W. This allowed me to remove the line and assert that the assumption
with a tilde in front of it was true. Note that IP tells us to put a tilde on
the assumption, not take one off.
Some further notes about indirect proofs:
1. They can be used to prove any statement in a proof, not just the conclusion.
2. The goal in IP is any statement of the form p
p, where p may be simple or compound. This
means that I don't have a specific p in mind. Thus IP's are often easier than
other proofs since often my method is just to derive as many statements as I can
(most of the time using the rules which break up statements) keeping my eyes open
for any two statements which contradict each other. When I find them, I put them
together by Conj to get my self-contradiction p
p. In the next proof with discovery
numbers you'll notice gaps where I wasn't after anything in particular--I was just
looking for two contradictory statements wherever they occurred. You'll also notice
that I have used an Indirect Proof inside of a conditional proof. Click here to see this proof.
Logical Truths
Logical truths are statements which
are true regardless of any factual considerations. When these are expressed in
propositional
logic, logical truths are tautologies. Since their truth does not depend upon
on fact, they can be derived from no premises at all. For example, look at this logical
truth (tautology):
A (A
v B)
A proof of it would be
| | 1. | A | ACP |
| | 2. | Av B | 1 Add |
| 3. | A |
1-2 CP |
| |1. | AIP | |
| |2. | 1 Impl. | |
| |3. | 2 DM | |
| |4. | 3 Com, Simp | |
| |5. | 4 DM | |
| |6. | 5 Simp | |
| |7. | 3 Simp | |
| |8. | 6, 7 Conj | |
| 9 | 1-8 IP | |
| 10 | A |
9 DN |
For help on using Logic Coach click here --> 
To send your homework to Dr. Redmon, click here--> 
Philosophy 222 --> Course Home Page